MCQ On Subnetting
Q1. What is the main purpose of subnetting?.
- Increase broadcast domain size
- Divide a network into smaller networks
- Increase IP address wastage
- Combine networks into one
Answer: b, Divide a network into smaller networks
Solution: Subnetting divides a large network into smaller ones.
Q2. What is the subnet mask for a /26 network?.
- 255.255.255.0
- 255.255.255.128
- 255.255.255.192
- 255.255.255.224
Answer: c, 255.255.255.192
Solution: /26 corresponds to 255.255.255.192.
Q3. A /27 network provides how many usable hosts?.
- 32
- 30
- 14
- 62
Answer: b, 30
Solution: /27 gives 32 addresses ? 30 usable.
Q4. Which of the following is the broadcast address of 192.168.1.64/26?.
- 192.168.1.126
- 192.168.1.127
- 192.168.1.63
- 192.168.1.95
Answer: d, 192.168.1.95
Solution: /26 block size 64 ? broadcast = 127.
Q5. What is the network address of 10.0.5.123/16?.
- 10.0.0.0
- 10.0.5.0
- 10.0.255.0
- 10.0.1.0
Answer: a, 10.0.0.0
Solution: /16 means first 16 bits are network ? 10.0.0.0.
Q6. In subnetting, borrowing more bits from host portion results in:.
- More hosts per subnet
- Fewer subnets
- More subnets but fewer hosts
- No change
Answer: c, More subnets but fewer hosts
Solution: More network bits ? more subnets, fewer hosts.
Q7. What is the block size for a /28 subnet?.
- 4
- 8
- 16
- 32
Answer: c, 16
Solution: /28 ? 4 host bits ? block size 16.
Q8. A company needs 50 hosts. Which subnet mask fits best?.
- /24
- /27
- /26
- /25
Answer: c, /26
Solution: /26 provides 62 usable hosts.
Q9. What is the usable host range of 172.16.10.0/24?.
- 172.16.10.0 – 172.16.10.255
- 172.16.10.1 – 172.16.10.254
- 172.16.10.1 – 172.16.10.253
- 172.16.10.2 – 172.16.10.254
Answer: b, 172.16.10.1 – 172.16.10.254
Solution: First is network, last is broadcast.
Q10. What does the /23 subnet mask represent?.
- Two Class C networks combined
- One Class B network
- Same as /24
- Same as /22
Answer: a, Two Class C networks combined
Solution: /23 merges two /24 networks.
Q11. How many subnets does a /26 create from a /24?.
- 2
- 4
- 8
- 16
Answer: b, 4
Solution: Borrowing 2 bits ? 2² = 4 subnets.
Q12. What is the first valid host in the 192.168.10.32/27 subnet?.
- 192.168.10.32
- 192.168.10.33
- 192.168.10.34
- 192.168.10.31
Answer: b, 192.168.10.33
Solution: First host = network + 1.
Q13. How many host bits remain in a /29 network?.
- 3
- 5
- 2
- 7
Answer: a, 3
Solution: /29 ? 3 host bits.
Q14. Which of the following masks supports 510 usable hosts?.
- /23
- /22
- /24
- /16
Answer: b, /22
Solution: /22 supports 1022 usable hosts ? enough for 510.
Q15. If a network is 200.10.20.0/25, what is the 2nd subnet?.
- 200.10.20.0
- 200.10.20.64
- 200.10.20.128
- 200.10.20.192
Answer: c, 200.10.20.128
Solution: /25 divides into blocks of 128 ? 0 & 128.